Question

Find the HCF of 16(x²-3x+2) and 24(x²-4x+3)​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

(x-1)

x2−3x+2=x2−2x−x+2

x(x−2)−1(x−2)=(x−2)(x−1)

Now

x2−4x+3=x2−3x−x+3

x(x−3)−1(x−3)=(x−3)(x−1)

Thus, the only common factor is (x-1)

Option A