Question

find the hcf of 163 and 52 express it as a linear combination of number 163m+52n​

Answer 1

Answer:

81 = 75 x 1 + 6 � Step 2

 

Since remainder 6 ? 0, we apply the division lemma to 75 and 6 to obtain

75 = 6 x 12 + 3 � Step 3

 

Since remainder 3 ? 0, we apply the division lemma to 6 and 3 to obtain

6 = 3 x 2 + 0 � Step 4

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

163=52x3+7

52=7x7+3

7=3x2+1

3=1x3+0

HCF =1

1=7-3x2

1=7-(52-7x7)x2

1=7-(52x2-7x14)=7x15-52x2

1=(163-52x3)x15-52x2

1=163x15-52x47

1=163x15+52x(-47)

Here ,m=15 & n=-47.

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