Math, asked by adehyadav2793, 1 year ago

Find the HCF of 1656 and 4025 by Euclid's method

Answers

Answered by sumo2
7
a=bq+r
here 4025=1656*2+713
1656=713*2+230
713=230*3+23
230=23*10+0
so remainder is zero here
hence hcf is 23
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