Question

find the HCF of 18,48

Answer 1

As 48 > 18, we will use Euclid's Division Lemma to find their H.C.F
i.e., a = bq + r, where 0 ≤ r < b,

Now,


⇒ 48 = 18 × 2 + 12 
⇒ 18 = 12 × 1 + 6
⇒ 12 =   6 × 2 + 0 

As division stops here, so we get,

H.C.F. (48,18) = 6

Now,
there's another way to solve this which is prime factorization method 

Here, prime factors of 48 and 18 are :-

48 = 2 × 2 × 2 × 2 × 3 
18 = 2 × 3 × 3 

Since 2 and 3 are common in both of them, 

we get,

H.C.F. (18,48) = 2 × 3
                       = 6


Thanks 

Answer 2

18=2×3×3

48=2×2×2×2×3

Since one 2 and a 3 is common,

HCF of (18,48) = 2×3 = 6.

Hope this helps you.Plz mark my answer as brainliest.