Find the HCF OF 180, 252 and 324 using
Euclid's division lemma
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First take the Hcf of 324 and 252 then whatever be the hcf divide it from 180 whatever will come be the Hcf of all three then arrange them in a=q×m+r
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H.C.F of 180,252,324
first we have to take out the H.C.F of any two no.
H.C.F of 252 and 324
using Euclid's division lemma
324=252×1+72
252=72×3+36
72=36×2+0
hence we get that H.C.F of 324 and 252 is 36.
then we have to find out the H.C.F of 36 and 180. that will be our answer
180=36×5+0
hence we get that H.C.F of 36 and 180 is 36 .
therefore 36 is our answer.
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