find the hcf of 180 , 252and324 using euclid division lemma
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252=180×1+72
180=72×2+36
72=36×2+0
(252,180)of hcf=36
324=252×1+72
252=72×3+39
79=39×2+0
(324,252)of hcf=39
is your answer
180=72×2+36
72=36×2+0
(252,180)of hcf=36
324=252×1+72
252=72×3+39
79=39×2+0
(324,252)of hcf=39
is your answer
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