find the HCF of 180 and 336 hence find their LCM
Answers
Answered by
109
336 = 180*1 + 156
180 = 156*1 + 24
156 = 24*6 + 12
24 = 12*2 + 0
HCF = 12
Product of two numbers = HCF*LCM
LCM = Product of two numbers/HCF
LCM = 180*336/12
LCM = 5040
180 = 156*1 + 24
156 = 24*6 + 12
24 = 12*2 + 0
HCF = 12
Product of two numbers = HCF*LCM
LCM = Product of two numbers/HCF
LCM = 180*336/12
LCM = 5040
aman193:
thanks
Answered by
32
HI !
a = bq + r
336 = 180 × 1 + 156
180 = 156 × 1 + 24
156 = 24 × 6 + 12
24 = 12 × 2 + 0
HCF = 12
Product of two numbers = HCF × LCM
Product of two numbers = 180 × 336 = 60480
LCM = Product of two numbers ÷ HCF
= 60480/12
= 5040
--------------------------------------------------------------
lcm × hcf will be equal to the product of only two numbers.
if there are more than two numbers , and we r asked to find its hcf and lcm , we use prime factorization method
a = bq + r
336 = 180 × 1 + 156
180 = 156 × 1 + 24
156 = 24 × 6 + 12
24 = 12 × 2 + 0
HCF = 12
Product of two numbers = HCF × LCM
Product of two numbers = 180 × 336 = 60480
LCM = Product of two numbers ÷ HCF
= 60480/12
= 5040
--------------------------------------------------------------
lcm × hcf will be equal to the product of only two numbers.
if there are more than two numbers , and we r asked to find its hcf and lcm , we use prime factorization method
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