Find the HCF of 190 and 145....with the help of EUCLID DIVISION ALGORITHM?
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Answered by
4
by euclid's division algorithm
190=145×1+45
145=45×3+10
45=10×4+5
10=5×2+0
hence in a=bq+r, b is considered as a hcf
hence the required hcf is 5
190=145×1+45
145=45×3+10
45=10×4+5
10=5×2+0
hence in a=bq+r, b is considered as a hcf
hence the required hcf is 5
Answered by
1
Heya!
Here is yr answer...........
According to Euclid division Algorithm
190 = 145 × 1 +45
145 = 45 × 3 +10
45 = 10 × 4 +5
10 = 5 × 2 +0
Here, divisor is the HCF.
Therefore, 5 is the HCF of 190 and 145
Hope it hlpzz....
Here is yr answer...........
According to Euclid division Algorithm
190 = 145 × 1 +45
145 = 45 × 3 +10
45 = 10 × 4 +5
10 = 5 × 2 +0
Here, divisor is the HCF.
Therefore, 5 is the HCF of 190 and 145
Hope it hlpzz....
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