Find the hcf of. 2^2×3^3,2×2×3×2×5,3^2×5
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Answered by
0
Answer:
it's 3
hope it helps you thanks
Answered by
0
Answer:
The HCF is 3
Step-by-step explanation:
Step 1:
Given that
2^2×3^3, 2×2×3×2×5, 3^2×5
Step 2:
That is in the simplest form
2 x 2 x 3 x 3 x 3 = 108
Step 3:
Prime factors of 108 = 2 × 2 × 3 × 3 × 3
Prime factors of 120 = 2 × 2 × 2× 3 × 5
Prime factors of 45 = 3 x 3 x 5 = 45
Step 4:
We need to find the HCF for 108,120 and 45 which is 3
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