Math, asked by laiqabutt743, 10 months ago

Find the hcf of. 2^2×3^3,2×2×3×2×5,3^2×5

Answers

Answered by krish4210911
0

Answer:

it's 3

hope it helps you thanks

Answered by lovingheart
0

Answer:

The HCF is 3

Step-by-step explanation:

Step 1:

Given that

2^2×3^3, 2×2×3×2×5, 3^2×5

Step 2:

That is in the simplest form

2 x 2 x 3 x 3 x 3 = 108

Step 3:

Prime factors of 108 = 2 × 2 × 3 × 3 × 3

Prime factors of 120 = 2 × 2 × 2× 3 × 5    

Prime factors of 45 = 3 x 3 x 5 = 45

Step 4:

We need to find the HCF for 108,120 and 45 which is 3

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