Math, asked by Bajaj2454, 11 months ago

Find the hcf of 2^3×3^2×5 and 2^2×3^3×5^2 and 2^4×3×5^3×7

Answers

Answered by SiddhantWaghmare
0

Answer:

(2^3)*(3^2)*(5)=2*2*2*3*3*5

(2^2)*(3^3)*(5^2)=2*2*3*3*3*5*5

(2^4)*(3)*(5^3)*(7)=2*2*2*2*3*5*5*5*7

common factor=2*2*3*5=60

Answered by rekhasharmananukanu
0

Answer:

Step-by-step explanation:

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