find the HCF of 2/3, 8/9, 10/27 a) 8/9 b) 10/3 c) 1/27 d) 5/6
Answers
Answer:
HCF(
3
2
,
9
8
,
81
64
,
27
10
)=
81
2
Step-by-step explanation:
Given : Fractions \frac{2}{3}, \frac{8}{9}, \frac{64}{81},\frac{10}{27}
3
2
,
9
8
,
81
64
,
27
10
To find : The HCF of fraction ?
Solution :
The highest common factor of fractions is given by,
\text{HCF of a Fraction}=\frac{\text{HCF of the numerators of the fractions}}{\text{LCM of the Denominators of the Fractions}}HCF of a Fraction=
LCM of the Denominators of the Fractions
HCF of the numerators of the fractions
HCF of the numerator 2,8,64,10
Factors of the number is
2=2\times 12=2×1
8=2\times2\times 28=2×2×2
64=2\times2\times2\times 2\times 2\times 264=2×2×2×2×2×2
10=2\times 510=2×5
HCF(2,8,64,10)=2HCF(2,8,64,10)=2
LCM of the denominator 3,9,81,27
3 | 3 9 81 27
3 | 1 3 27 9
3 | 1 1 9 3
3 | 1 1 3 1
| 1 1 1 1
LCM(3,9,81,27)=3\times3\times 3\times 3=81LCM(3,9,81,27)=3×3×3×3=81
So, HCF of \frac{2}{3}, \frac{8}{9}, \frac{64}{81},\frac{10}{27}
3
2
,
9
8
,
81
64
,
27
10
\text{HCF}(\frac{2}{3}, \frac{8}{9}, \frac{64}{81},\frac{10}{27})=\frac{2}{81}HCF(
3
2
,
9
8
,
81
64
,
27
10
)=
81
2
#Learn more
HCF of 2/3,8/9,64/81,10/27 is