Find the HCF of 2(x2-y2) and 5(x3-y3)
Answers
Answered by
0
Step-by-step explanation:
please mark me as brainliest and follow me.
Answer: The H.C.F. of polynomials x2-y2 and x3-y3 is (x-y). In both expressions, (x-y) is common factor. Therefore H.C.F. of polynomials x2-y2 and x3-y3 is (x-y)
Similar questions
Math,
5 months ago
Social Sciences,
5 months ago
Science,
10 months ago
Math,
10 months ago
Math,
1 year ago