Math, asked by prabhuspsmech19721, 12 days ago

find the hcf of 20,48,72 using prime factorisation

Answers

Answered by soumyajha5d872r33
0

prime factorization of 20 = 2×2×5

48= 2×2×2×2×3

72= 2×2×2×3×3×3

maximum number of 2 in all the factorization = 2 times

2×2 = 4

L.C.M = 4

Answered by aftabahemad
1

Answer:

HCF of the given number will be 4

Step-by-step explanation:

In context to question asked,

We have to determine the HCF

As per question,

We have,

20, 48, 72

As it is mentioned to determine the HCF by using prime factorisation method.

We know that,

  • HCF of two or more number is that particular number which is the highest common factors of all the given number.
  • Prime factorisation method is the method in which we convert the given number as a factors of prime numbers.
  • Prime numbers are those numbers which are either divisible by 1 or itself.
  • HCF of any prime number is always 1

So, converting the given number in form of prime numbers,

We will get,

20 = 2 \times 2 \times 5\\72 =3 \times 2 \times 2 \times 2 \times 3\\48 = 2 \times 2 \times 3 \times 2 \times 2\\HCF = 2 \times 2 = 4\:(Common\:Number)

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