find the HCF of 20 64 104 by division method
Answers
Answered by
38
Hope it helps you
............ HCF = 4 ||||||||||| 20 = 2×2×5 64 = 2×2×2×2×2×2 104 = 2×2× 13. Here, two 2 are common in these numbers therefore The HCF OF 20,64,104 = 2×2 = 4. 20 = 2×2×5 64 = 2×2×2×2×2×2 104 = 2×2× 251. Here, two 2 are common in these numbers therefore The HCF OF 20,64,104 = 2×2 = 4.
............ HCF = 4 ||||||||||| 20 = 2×2×5 64 = 2×2×2×2×2×2 104 = 2×2× 13. Here, two 2 are common in these numbers therefore The HCF OF 20,64,104 = 2×2 = 4. 20 = 2×2×5 64 = 2×2×2×2×2×2 104 = 2×2× 251. Here, two 2 are common in these numbers therefore The HCF OF 20,64,104 = 2×2 = 4.
Attachments:
mysticd:
Therefore , HCF ( 20 , 64 , 104 ) = 4
How can u conclude hcf
How many chp u finished
Anyone tgerr
the divisor of last division is the HCF
Answered by
13
20= 2×2×5×1
64=2×2×2×2×2×2×1
104=2×2×2×13×1
Hcf= 2×2= 4
64=2×2×2×2×2×2×1
104=2×2×2×13×1
Hcf= 2×2= 4
This is prime factorization method not division method
Ok sorry i will do it now
Similar questions