find the hcf of 20,64,104 by euclids division lemma
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20 = 2×2×5
64 = 2×2×2×2×2×2
104 = 2×2× 2×13
Here,
two 2 are common in these numbers therefore The HCF OF 20,64,104 = 2×2 = 4.
64 = 2×2×2×2×2×2
104 = 2×2× 2×13
Here,
two 2 are common in these numbers therefore The HCF OF 20,64,104 = 2×2 = 4.
swaminathan007:
Ur wrong this is prime factorization and in 104 it is 2×2×2×13 u have written 251 ur wrong
plz
msg me......
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