Find the hcf of 20 and 28 using listing method
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Answer:
4 is the answer of this question
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Answer:
Factors of 20 = F(20) = { 1,2,4,5,10,20 }
28 = 1 × 28.
= 2 × 14.
= 4 × 7.
Factors of 28 = F(28) = { 1, 2 , 4, 7, 14, 28 }
Common factors of 20 and 28 = { 1, 2, 4 }
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