Math, asked by arcotisrinidhi, 6 months ago

find the HCF of 21x(x²-1)&3x³(x+1)​

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Answers

Answered by karupsr1976
3

Answer:

=3x4+24x3−21x

Step-by-step explanation:

21x(x2−1)+3x3(x+1)

Distribute:

=(21x)(x2)+(21x)(−1)+(3x3)(x)+(3x3)(1)

=21x3+−21x+3x4+3x3

Combine Like Terms:

=21x3+−21x+3x4+3x3

=(3x4)+(21x3+3x3)+(−21x)

=3x4+24x3+−21x

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