Find the HCF of 225 and 135 using Euclid's Division Lemma.
Explain step by step the process of solving this.
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Answered by
2
Here 225 is greater than 135. We always divide greater number with the smaller one.
Divide 225 by 135 we get 1 quotient and 90 as remainder so that
225=135*1+90
Divide 135 by 90 we get 1 quotient and 45 as remainder so we can write it as
90=2*45+0
As there are no remainder so 45 is our HCF
Divide 225 by 135 we get 1 quotient and 90 as remainder so that
225=135*1+90
Divide 135 by 90 we get 1 quotient and 45 as remainder so we can write it as
90=2*45+0
As there are no remainder so 45 is our HCF
SarthakBhan:
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Answered by
4
according to Euclid's Divison method ,
a = br + c
135 )225( 1
135
==========
90
hence, we write this according to Euclid theorem ,
225 = 135 x 1 + 90
again ,
90)135( 1
90
========
45
write a/c to Euclid theorem ,
135 = 90 x 1 + 45
again,
45)90( 2
90
=========
00
a/c to Euclid theorem ,
90 = 2 x 45
hence, 45 is HCF of (225 , 135 )
================================
another way of Euclid theorem ,
factors of 225 = 5 x 5 x 3 x 3
facotors of 135 = 5 x 3 x 3 x 3
we know,
HCF is the Highest common factors of all given numbers
so, common factor of 225 and 135 = 5 x 3 x 3 = 45
so, HCF of (225 , 135) = common factors of (225 , 135) = 45
a = br + c
135 )225( 1
135
==========
90
hence, we write this according to Euclid theorem ,
225 = 135 x 1 + 90
again ,
90)135( 1
90
========
45
write a/c to Euclid theorem ,
135 = 90 x 1 + 45
again,
45)90( 2
90
=========
00
a/c to Euclid theorem ,
90 = 2 x 45
hence, 45 is HCF of (225 , 135 )
================================
another way of Euclid theorem ,
factors of 225 = 5 x 5 x 3 x 3
facotors of 135 = 5 x 3 x 3 x 3
we know,
HCF is the Highest common factors of all given numbers
so, common factor of 225 and 135 = 5 x 3 x 3 = 45
so, HCF of (225 , 135) = common factors of (225 , 135) = 45
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