Math, asked by AnanthaShayana, 3 months ago

Find the HCF of 24 45 57 by prime factorization method

Answers

Answered by SoyanshuMohapatra
4

Answer:

HCF(24, 45, 57) = 3

Step-by-step explanation:

24 = 2 × 2× 2 × 3

45 = 3× 3 × 5

57 = 3 × 29

Answered by Anonymous
6

Answer:

answer = 3

Step-by-step explanation:

1. decompose all number into prime factor

24| 2 45|3 57|3

12 | 2 15|3 9|19

6 | 2 5|5 1|

3 | 3 1|

1 |

2. write all the number as a product of its prime factors

prime factor of 24 = 2³ . 3

prime factor of 45 = 3² . 5

prime factor of 57 = 3 . 19

3. choose the common prime factor with the lowest exponent

common prime factors: 3

common prime factors with the lowest

exponents : 3¹

4. calculate the the greatest common factor or GCF

★ remember to find GCF of several number you must multiply the common prime factor with the lowest exponent

GCF = 3¹ = 3

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