Find the HCF of 240 and 6552 and express it in the form 6552x+240y where x and y are Integers.Also find the value of x and y.
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a= bq + r
6552=240×27+72
240=72×3+24
72=24×3+10
Therefore HCF is 24.
24=240-72×3
=240-(6552-240×27)×3
=240-6552+240×27×3
=240×1+240×81-6552×3
=240(1+81) +6552(-3)
=240(82) + 6552(-3)
x=-3 y=82
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