find the HCF of 250 and , 30
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By using Euclid's division lemma, we get,
250=30×8+10
Now, consider the divisor and remainder.
Again by using Euclid's division lemma, we get,
30=10×3+0
Here, we notice the remainder is zero and we cannot proceed further.
The divisor at this stage is 10.
The HCF of 250 and 30 is 10.
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