find the hcf of 255050,185 by euclid's division algorithm
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Step-by-step explanation:
this is going to be a very long method
255050=185×1378+120
185=120×1+65
120=65×1+55
65=55×1+10
55=10×5+5
10=5×2+0
since 5 is the last divisor, the HCF of 255050 and 185 is 5
hope you find it helpful
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