Find the hcf of 25920 and 54432 using prime factorization method
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Prime factorisation of 25920 & 54432
➡ 25920 = 2×2×2×2×2×2×3×3×3×3×5
➡ 54432 = 2×2×2×2×2×3×3×3×3×3×7
Common factors = 2×2×2×2×2×3×3×3×3
= 2592
So, HCF = 2592.
Answer :-
HCF ( 25920, 54432 ) = 2592
Hope it will help you !!!
➡ 25920 = 2×2×2×2×2×2×3×3×3×3×5
➡ 54432 = 2×2×2×2×2×3×3×3×3×3×7
Common factors = 2×2×2×2×2×3×3×3×3
= 2592
So, HCF = 2592.
Answer :-
HCF ( 25920, 54432 ) = 2592
Hope it will help you !!!
Answered by
6
Hey! ! !
Mate :-
______________________________________________________________________
Question :- ☆ Find the hcf of 25920 and 54432 using prime factorization method
Solution :-
prime factor of
☆ 25920 = 2*6 × 3*4 × 5
☆ 54432 = 2*5 × 3*4 × 7
So that
Hcf ( Highest common factor)
= 2*5 × 3*4
= 2,592
_______________________________________________^______________________
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
Mate :-
______________________________________________________________________
Question :- ☆ Find the hcf of 25920 and 54432 using prime factorization method
Solution :-
prime factor of
☆ 25920 = 2*6 × 3*4 × 5
☆ 54432 = 2*5 × 3*4 × 7
So that
Hcf ( Highest common factor)
= 2*5 × 3*4
= 2,592
_______________________________________________^______________________
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
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