Math, asked by jaanviv6258, 1 day ago

Find the HCF of 27 81 and 18

Pls answer I am in trouble ​

Answers

Answered by munnishebeer
2

Step-by-step explanation:

HCF of 27 and 63 is the largest possible number that divides 27 and 63 exactly without any remainder. The factors of 27 and 63 are 1, 3, 9, 27 and 1, 3, 7, 9, 21, 63 respectively.

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HCF of 27 and 63.

To find the HCF of 81 and 237, we will find the prime factorization of the given numbers, i.e. 81 = 3 × 3 × 3 × 3; 237 = 3 × 79. ⇒ Since 3 is the only common prime factor of 81 and 237. Hence, HCF (81, 237) = 3.

Factors of 18 = 1, 2, 3, 6, 9 and 18. Therefore, common factor of 12 and 18 = 1, 2, 3 and 6. Highest common factor (H.C.F) of 12 and 18 = 6 [since 6 is the highest common factor].

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Answered by geetanjali61075
3

Answer:

the answer is :-

9

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