Math, asked by annonymus1789, 10 months ago

find the HCF of 270,945,2175 by divison method​

Answers

Answered by abdulqadir52
20

Answer:

the answer is 15

Step-by-step explanation:

please mark it as brainliest answer

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Answered by payalchatterje
1

Answer:

The HCF of 270,945,2175 is 15

Step-by-step explanation:

Given three numbers are 270,945,2175.

Here we want to find HCF of these given numbers.

But now question is what is HCF ?

We know HCF means Highest Common Factor.

For example,we are taking two numbers 15 and 24.

Now we are dividing 24 by 15 and get 1 as quotient and 9 as remainder.

Again 15 is dividing by 9 and get 1 as quotient and 6 as remainder.

Now 9 is dividing by 6 and get 1 as quotient and 3 as remainder.

again 6 is dividing by 3 and get 2 as quotient and 0 as remainder.

According to Division rule of HCF,

3 is HCF of 15 and 24.

Here given three numbers are 270,945,2175.

First 2175 is dividing by 945 and get 2 as quotient and 285 as remainder.

Again 945 is dividing by 285 and get 3 as quotient and 90 as remainder.

Now 285 is dividing by 90 and get 3 as quotient and 15 as remainder.

Again 90 is dividing by 15 and get 6 as quotient and there is no remainder.

Now,270 is dividing by 15 and get 18 as quotient and no remainder.

According to Division rule of HCF,

HCF of 270,945,2175 is 15.

Know more about HCF,

https://brainly.in/question/25945206

https://brainly.in/question/20353612

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