Question

find the hcf of 274170 and 17017 by e.d.l

Answer 1

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Hcf = 13

274170=17017×16+1898

17017=1898×1+1833

1898 = 1833×1+65

1833= 65×28+13

65= 13×5+0

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Answer 2

274170=17017×16+1898

17017=1898×1+1833

1898 = 1833×1+65

1833= 65×28+13

65= 13×5+0

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