Find the hcf of 275 and 200 . And please express it in the form of 275x+200y. Please express using RD sharma method class 10th .
Answers
Answered by
1
Hey!!!
Good Afternoon champ
_______________
For HCF(200,275),By Euclid's Division Lemma,
=> 275 = 200 x 1 + 75 ---------(2)
=> 200 = 75 x 2 + 50 --------(1)
=> 75 = 50 x 1 + 25 <<<<<<<< answer
=> 50 = 25 x 2 + 0
Thus HCF = 25
Expression part
We have
=> 75 = 50 x 1 + 25
=> 25 = 75 - (50 x 1)
Now replace 50 from (1)
=> 25 = 75 - [200 - (75 x 2)]
=> 25 = 75 - 200 + (75 x 2)
=> 25 = 75(3) - 200(1)
Now replace 75 from (2)
=> 25 = [275 - (200 x 1)]3 - 200(1)
=> 25 = 275(3) - 200(4)
=> 25 = 275x + 200y <<<< Answer
where x = 3 and y = - 4
Verification :
=> 275(3) - 200(4)
=> 825 - 800
=> 25
______________
Hope this helps ✌️
Have a marvelous Monday Ahead
Good Afternoon champ
_______________
For HCF(200,275),By Euclid's Division Lemma,
=> 275 = 200 x 1 + 75 ---------(2)
=> 200 = 75 x 2 + 50 --------(1)
=> 75 = 50 x 1 + 25 <<<<<<<< answer
=> 50 = 25 x 2 + 0
Thus HCF = 25
Expression part
We have
=> 75 = 50 x 1 + 25
=> 25 = 75 - (50 x 1)
Now replace 50 from (1)
=> 25 = 75 - [200 - (75 x 2)]
=> 25 = 75 - 200 + (75 x 2)
=> 25 = 75(3) - 200(1)
Now replace 75 from (2)
=> 25 = [275 - (200 x 1)]3 - 200(1)
=> 25 = 275(3) - 200(4)
=> 25 = 275x + 200y <<<< Answer
where x = 3 and y = - 4
Verification :
=> 275(3) - 200(4)
=> 825 - 800
=> 25
______________
Hope this helps ✌️
Have a marvelous Monday Ahead
Shiwanikhatik:
Thank you.......
Similar questions