Question

find the hcf of 28 48 and 72 by prime factorization​

Answer 1

$\textbf{Given:}$

$\textsf{Numbers are 28, 48, 72}$

$\textbf{To find:}$

$\textsf{HCF of 28, 48, 72}$

$\textbf{Solution:}$

$\textsf{Consider,}$

$\mathsf{28=2^2{\times}7}$

$\mathsf{48=2^4{\times}3}$

$\mathsf{72=2^3{\times}3^2}$

$\mathsf{Clearly\;2^2\;is\;common\;factor}$

$\implies\boxed{\mathsf{HCF=4}}$

$\textbf{Answer:}$

$\textsf{HCF of the given numbers is 4}$

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