Math, asked by sritanvi33, 1 month ago

find the hcf of 2x^2+4x+2 and 6x^2+18x+12​

Answers

Answered by adinasaleem56
0

Answer:

HCF is (x+1)

Step-by-step explanation:

2x^2+4x+2= 2x^2+2x+2x+2

= 2x(x+1)+2(x+1)

= (2x+2)(x+1)

6x^2+18x+12= 6x^2+6x+12x+12

= 6x(x+1)+12(x+1)

= (6x+12)(x+1)

HCF = common factor

= (x+1)

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