find the HCF of 3 24/46 and 4 18/92
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Sol. I. 126 = 2 × 3 × 3 × 7 = 2 × 32 × 7
396 = 2 × 2 × 3 × 3 × 11 = 22 × 32 × 11
5400 = 2 × 2 × 2 × 3 × 3 × 3 × 5 × 5 = 23 × 33 × 52
II. The factors common to all the given numbers are 2 and 3 and their lowest powers are 1 (21) and 2 (32) respectively. Only the product of 2 and 32 can divide all the given numbers.
HCF = 2 × 32 = 18 Ans.
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Sorry to say but it is so easy you should try it
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