find the HCF of 306 and 657.also find their LCM using HCF
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2
yo dude....☺️
ur answer is in the attachment...✌️
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ANKITA❤️
ur answer is in the attachment...✌️
hope it hlps!!!!✨
Regards,
ANKITA❤️
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Answered by
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edl_a=bq+r.
let a be 657, b be 306
657=306×2+45
306=45×6+36
45=36×1+9
36=9×4+0
when r=0, then hcf(657,306)=9.
wkt,
lcm×hcf= ab
lcm×9=306×657
lcm=306×657÷9
=22338.
let a be 657, b be 306
657=306×2+45
306=45×6+36
45=36×1+9
36=9×4+0
when r=0, then hcf(657,306)=9.
wkt,
lcm×hcf= ab
lcm×9=306×657
lcm=306×657÷9
=22338.
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