Question

find the hcf of 32, 80, 160

Answer 1

Given numbers:-

$32, 80, 160$

To find the HCF of the given numbers,

Now, by factorizing the given numbers, we get

$=>32=2^5$

$=>80=2^4*5$

$=>160=2^5*5$

By comparing all the above (3) factors,

We will get the common factor as

$=>2^4$

Therefore,

Greatest common factor = $16$

Answer 2

From the given question the correct answer is:

the HCF of 23,80,160 is 16.

Given :

32, 80, 160

To find:

the HCF of 32,80,160.

solution:

first, we will  factorized  the numbers,

we get,

32=$2^{5}$

80=$2^{4} * 5$

160=$2^{5} * 5$

By comparing all the above (3) factors,

We will get the common factor as

$2^{4}$

Therefore,

Greatest common factor = 16.

thus the HCF of 23,80,160 is 16.