find the HCF of 36 and 96 and 120 by euclid's Lemma
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On applying euclid's division Lemma for 36 and 96
96 = 36 ×2 + 24
Here, Remainder = 24≠0
So take new Dividend as 36 and divisor as 24.
36 = 24×1 +12
Here, Remainder = 12≠0
So take new Dividend as 24 and divisor as 12.
24 = 12×2 +0
Here, the Remainder = 0 and the last divisor is 12.
So, HCF of 36 and 96 is 12.
On applying euclid's division Lemma for 12 and 120
120 = 12 ×10 + 0
Here Remainder = 0
So , HCF of 36, 96 and 120 is 12.
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96 = 36 ×2 + 24
Here, Remainder = 24≠0
So take new Dividend as 36 and divisor as 24.
36 = 24×1 +12
Here, Remainder = 12≠0
So take new Dividend as 24 and divisor as 12.
24 = 12×2 +0
Here, the Remainder = 0 and the last divisor is 12.
So, HCF of 36 and 96 is 12.
On applying euclid's division Lemma for 12 and 120
120 = 12 ×10 + 0
Here Remainder = 0
So , HCF of 36, 96 and 120 is 12.
HOPE THIS WILL HELP YOU....
if correct say thanks
Answered by
4
Answer:
Step-by-step explanation:
On applying euclid's division Lemma for 36 and 96
96 = 36 ×2 + 24
Here, Remainder = 24≠0
So take new Dividend as 36 and divisor as 24.
36 = 24×1 +12
Here, Remainder = 12≠0
So take new Dividend as 24 and divisor as 12.
24 = 12×2 +0
Here, the Remainder = 0 and the last divisor is 12.
So, HCF of 36 and 96 is 12.
On applying euclid's division Lemma for 12 and 120
120 = 12 ×10 + 0
Here Remainder = 0
So , HCF of 36, 96 and 120 is 12
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