Find the hcf of 367 and 225 by division algorithm
Answers
Answered by
1
answer: 1
solution:
367=225x1+142
225=142x1+83
142=83x1+59
83=59x1+24
59=24x2+11
24=11x2+2
11=2x5+1
2=1x2+0
remainder is 0, so hcf= divisor= 1
Hope it helped!!
solution:
367=225x1+142
225=142x1+83
142=83x1+59
83=59x1+24
59=24x2+11
24=11x2+2
11=2x5+1
2=1x2+0
remainder is 0, so hcf= divisor= 1
Hope it helped!!
Similar questions