Question

find the hcf of 36and25by using EDL​

Answer 1

Answer:

$a = bq + r$

$36 = 25(1) + 11 \\ 25 = 11(2) + 3 \\ \\ 11 = 3(3) + 2 \\ 3 = 2(1) + 1 \\ 2 = 2(1) + 0$

hcf = 2

Answer 2

Answer:

a=bq+r

36=25(1)+11

25=11(2)+3

11=3(3)+2

3=×(1)+1

2=2(1)+0

hcf =2