find the HCF of 40,36,126 by euclids division algorithm?
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Answer:
2
Step-by-step explanation:
First, find the prime factors of the given integers: 40, 36 and 126.
For, 40 = 2 x 2 x 2 × 5.
36 = 2 x 2 x 3 x 3.
126 = 2 × 3 × 3 × 7.
Now, L.C.M of 40, 36 and 126 = 23 × 32 × 5 × 7.
∴ L.C.M (40, 36, 126) = 2520.
And, H.C.F (40, 36 and 126) = 2.
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