Math, asked by ajaysingh657665, 18 hours ago

find the HCF of 4052 and12576..

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Answers

Answered by rityahir
0

Answer:

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Answered by ItzStrawBerry
1

Prime factorization of 4052 and 12576 is (2 × 2 × 1013) and (2 × 2 × 2 × 2 × 2 × 3 × 131) respectively.

As visible, 4052 and 12576 have common prime factors.

Hence, the HCF of 4052 and 12576 is 2 × 2 = 4.

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