Question

Find the Hcf of 42 45 and 48

Answer 1

Answer:

hcf=3

42 45 48 are divisible by 3

and later we get 13 14 15 cant be further factorise in hcf

Answer 2

Answer:

$\red{QUESTION}$

Find the Hcf of 42 45 and 48

$\blue{ANSWER}$

WHAT IS HCF

HCF: HIGHEST COMMON FACTOR: THE HIGHEST FACTOR WHICH IS DIVISIBLE BY ALL THE GIVEN SETS OF NUMBERS.

IN THE ABOVE QUESTION

GIVEN NUMBERS: 42, 45, AND 48

42=

2|42

3|21

7|7

1|1

42 = 2×3×7

45=

3|45

3|15

5|5

1 |1

=3×3×5

48=

3|48

2|16

2|8

2|4

2|2

1|1

=3×2×2×2×2

COMMON FACTORS IN ALL THE THREE NUMBERS=

=3

SO HCF= 3

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METHODS OF FINDING HCF

• PRIME FACTORISATION METHOD: IN THIS METHOD WE FACTORISE THE GIVEN NO.S INTO PRODUCT OF PRIMES AND THEN WE CHOOSE THE COMMON FACTORS AMONG THE NUMBERS. WE MULTIPLY ALL THE COMMON FACTORS AND HENCE WE CAN FIND HCF

• DIVISION METHOD: IN THIS METHOD WE FIND HCF OF ONLY 2 GIVEN NUMBERS. WE DIVIDE THE LARGER NUMBER BY THE SMALLER NO. THEN WE DIVIDE THE DIVISOR BY THE REMAINDER AND CONTINUE THE STEPS TILL THE REMAINDER BECOMES 0. THE POINT AT WHICH REMAINDER IS 0, THE DIVISOR AT THAT POINT IS THE HCF OF 2 NUMBERS.