find the HCF of 4215,2145
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Answer:
15
Step-by-step explanation:
2,145 = 3 × 5 × 11 × 13;
4,215 = 3 × 5 × 281;
Multiply all the common prime factors, by the lowest exponents.
Greatest (highest) common factor (divisor):
gcf, hcf, gcd (2,145; 4,215) = 3 × 5
gcf, hcf, gcd (2,145; 4,215) = 3 × 5 = 15;
the numbers have common prime factors
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