find the HCF of 45 AND 27
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3
45 - 3×3×5
27 - 3×3×3
HCF = 3×3 = 9
27 - 3×3×3
HCF = 3×3 = 9
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0
applying euclid"s division algorithm,
45=27×1+18
27=18×1+9
18=9×2+0
the remainder at the stage is 0,
so the hcf is 9
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