Math, asked by DarkxAmber, 4 months ago

find the HCF of 48,36,24 by prime factorisation​

Answers

Answered by cutiepieangel123
7

Answer:

step 1

Address the method, input parameters & values

Integers: 24, 36, 48

find gcf (24, 36 and 48) = ?

step 2

Find the prime factors of all integers of the group

24 = 2 x 2 x 2 x 3

36 = 2 x 2 x 3 x 3

48 = 2 x 2 x 2 x 2 x 3

step 3

The common prime factor or the product of all common prime factors between all integers is the highest common factor of this group of integers (24, 36 & 48).

HCF(24, 36, 48) = 12

Answered by Anonymous
44

Answer:

Problem & Workout :

step 1 -- Address the method, input parameters & values

Integers: 24, 36, 48

find gcf (24, 36 and 48) = ?

Step 2 - Find the prime factors of all integers of the group

24 = 2 x 2 x 2 x 3

36 = 2 x 2 x 3 x 3

48 = 2 x 2 x 2 x 2 x 3

step 3 _ The common prime factor or the product of all common prime factors between all integers is the highest common factor of this group of integers (24, 36 & 48).

GCF(24, 36, 48) = 12

I hope it helps u ☺️.......

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