find the HCF of 48,36,24 by prime factorisation
Answers
Answered by
7
Answer:
step 1
Address the method, input parameters & values
Integers: 24, 36, 48
find gcf (24, 36 and 48) = ?
step 2
Find the prime factors of all integers of the group
24 = 2 x 2 x 2 x 3
36 = 2 x 2 x 3 x 3
48 = 2 x 2 x 2 x 2 x 3
step 3
The common prime factor or the product of all common prime factors between all integers is the highest common factor of this group of integers (24, 36 & 48).
HCF(24, 36, 48) = 12
Answered by
44
Answer:
Problem & Workout :
step 1 -- Address the method, input parameters & values
Integers: 24, 36, 48
find gcf (24, 36 and 48) = ?
Step 2 - Find the prime factors of all integers of the group
24 = 2 x 2 x 2 x 3
36 = 2 x 2 x 3 x 3
48 = 2 x 2 x 2 x 2 x 3
step 3 _ The common prime factor or the product of all common prime factors between all integers is the highest common factor of this group of integers (24, 36 & 48).
GCF(24, 36, 48) = 12
I hope it helps u ☺️.......
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