find the hcf of 48 72 and 108
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5
Answer:
Given numbers are 48, 72 and 108
Here, 22 × 31 are the smallest powers of the common factors 2 and 3 respectively. 24 × 33 are the greatest powers of the prime factors 2 and 3 respectively involved in the given three numbers .
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1
Answer:
12
Step-by-step explanation:
Here, 22 × 31 are the smallest powers of the common factors 2 and 3 respectively. So, HCF (48, 72, 108) = 2 × 2 × 3 = 12Read more on Sarthaks.com - https://www.sarthaks.com/920567/find-lcm-and-hcf-of-the-integers48-72-and-108-by-using-prime-factorization-method
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