find the HCF of 48,84 88 by prime factor method
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Answered by
34
Answer :
Now,
48 = 2 × 2 × 2 × 2 × 3
84 = 2 × 2 × 3 × 7
88 = 2 × 2 × 2 × 11
So, the common factors are 2 and 2
Hence, HCF (48, 84, 88) = 2 × 2 = 4.
#MarkAsBrainliest
Now,
48 = 2 × 2 × 2 × 2 × 3
84 = 2 × 2 × 3 × 7
88 = 2 × 2 × 2 × 11
So, the common factors are 2 and 2
Hence, HCF (48, 84, 88) = 2 × 2 = 4.
#MarkAsBrainliest
Amrita1111111111:
how can be the HCF 48 ,84 ,88
ok it's right
Answered by
15
By prime factorization
48= 2×2×2×2×3
84 = 2×2×3×7
88= 2×2×2×11
HCF [48, 84 and 88] = 2×2 = 4. => Answer
Hope it will helps you:-)
48= 2×2×2×2×3
84 = 2×2×3×7
88= 2×2×2×11
HCF [48, 84 and 88] = 2×2 = 4. => Answer
Hope it will helps you:-)
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