Question

Find the HCF of 48250 and 38540 using Euclid's division algorithm.

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Answer 1

$\huge \mathscr \red{Answer : }$

$\red{48250=38540×1+9710} \\ \\ </p><p> \green{39540=9710×3+9410} \\ \\ </p><p> \purple{9710=9410×1+300} \\ \\ </p><p> \pink{9410=300×31+110 }\\ \\ </p><p> \gray{300=110×2+80} \\ \\ </p><p> \orange{110=80×1+30} \\ \\ </p><p> \bold{80=30×2+20} \\ \\ </p><p>20=10×2+0 \\ \\ </p><p> \blue {Hence \: \: HCF \: \: of \: \: 38540 \: \: and \: \: 48250 \: \: is \: \: 10}$

Hope it will help you mate.....

Answer 2

$\huge\bf\underline\green{Question}$

Find the HCF of 48250 and 38540 using Euclid's division algorithm.

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$\huge\bf\underline\green{Answer}$

$\rm{➝~As,~ 48250~ > ~38540}$

$\rm{➝~a~ =~ bq ~+~ r}$

$\rm{➝~48250~ = ~38540 ~× ~1 ~+~ 9710}$

$\rm{➝~38540 ~= ~9710 ~× ~3 ~+ ~9410}$

$\rm{➝~9710 ~= ~9410 ~× ~1~ + ~300}$

$\rm{➝~9410 ~= ~300 ~× ~31 ~+ ~110}$

$\rm{➝~300 ~= ~110 ~× ~2 ~+~ 80}$

$\rm{➝~110 ~= ~80 ~× ~1~ + ~30}$

$\rm{➝~80~ = ~30 ~× ~2 ~+ ~20}$

$\rm{➝~30 ~= ~20 ~×~ 1 ~+ ~10}$

$\rm{➝~20~ = ~10 ~× ~2 ~+~ 0}$

$\rm\red{✰~Hence, ~the~ HCF~ of ~48250~ and~ 38540 ~is ~10}$

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