find the HCF of 496 and 21 24 by euclid 's division algorithm
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Euclid's Division Lemma
If 'a' and 'b' are two positive integers (a > b) their exist unique integers q and r such that a = bq + r , when 0 ≤ r < b
q = quotient
a = dividend
r = remainder
Algorithm ⇒ It is series of well defined steps which gives a procedure for solving a type of problem.
Lemma ⇒ It is proven statement used for another statement.
Now,
Answer
HCF of 496 and 2124
Here let a = 2124 and b = 496
so,
a = bq + r
2124 = 496 × 4 + 140
now, r ≠ 0
we take a = 496 and b = 140
496 = 140 × 3 + 76
now, r ≠ 0
we take a = 140 and b = 76
140 = 76 × 1 + 64
now, r ≠ 0
we take a = 76 and b = 64
76 = 64 × 1 + 12
now, r ≠ 0
we take a = 64 and b = 12
64 = 12 × 5 + 4
now, r ≠ 0
we take a = 12 and b = 4
12 = 4 × 3 + 0
now r = 0
Hence,
HCF (2124, 496) = 4
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