Question

Find the hcf of 52 &117 and express it in the form 52x + 117y

Answer 1

Answer:

Solution:-

By Euclid's Division Lemma 117 > 52

117 = (52 × 2) + 13 (52 is the divisor)

52 = 13 × 4 + 0 ; The division process ends here, as remainder is 0. So, HCF is 13 (Here, 13 is divisor)

13 can also be expressed as 52x + 117y i.e. as 52 (-2) + 117 (1)