Math, asked by ragul5, 1 year ago

find the HCF of 52 and 117 and also find the value of x and y if it is expressed in the form of 52x + 117 y

Answers

Answered by Anonymous
19
Heya,,,,
Ur answer is here
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we Find HCF of (52 , 117 )
using Euclid's Algorithm formula-

On applying Euclid's Algorithm
dividing 117 by 52, we get quotient = 2 and remainder is 13
=> 117 = 52 × 2 + 13

Again on applying Euclid's Algorithm on dividing 52 by 13 , we get
quotient =4 and remainder is 0.

In this step the remainder is zero.
Thus, the division I.e. 4 in this step is the H.C.F of the given Numbers
The HCF of 52 and 117 is 4.

Now,
=> 13 = ( 117 × 1 ) - ( 52 × 2 )

=> 13 = - (52 × 2) + (117 × 1 )

=> 13 = 52x + 117y

=> x = (-2) , y = 1

THEREFORE , HCF OF 52 and 117 is of the form 52x + 117 y ,
where , x = -2 and y = 1

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∆Hope it's helps you.

@isharoy688
Thank you ☺☺
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