Question

find the HCF of 52 and 117 and express it in form 52x+117y??
(class 10 CH 1)

Answer 1

Hope this helps you ☺☺

Answer 2

Let us find HCF of 52 and 117 by Euclid's division algorithm.
Since 117>52
117 = 52 × 2 + 13
52 = 13 × 4 + 0
Therefore HCF (52, 117) = 13

Now, 13 = 52×(-2) + 117×1
13 = 52x + 117y where X = -2 and y = 1