Find the HCF of 52 and 117 and express it in the form 52x +117y.
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Hcf of 52 and 117 is hcf of 4*13 and 9*13
So hcf is 13
13 = - 2*52 + 117*1
So x=-2 and y = 1
So hcf is 13
13 = - 2*52 + 117*1
So x=-2 and y = 1
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