Question

Find the HCF of 52 and 117 and express it in the form 52x + 117y.​

Answer 1

Step-by-step explanation:

o, HCF is 13 (Here, 13 is divisor) 13 can also be expressed as 52x + 117y i.e. as 52 (-2) + 117 (1). bolivianouft and 883 ...

Answer 2

Answer :

HCF(52 , 117) = 13 = 52×(-2) + 117×1

Solution :

Here ,

We need to find the HCF of 52 and 117 and express it in the form of 52x + 117y .

Let's find the HCF of 52 and 117 by long division method .

52 ) 117 ( 2

- 104

13 ) 104 ( 8

- 104

× ×

Hence ,

HCF(52 , 117) = 13

Also ,

We know that ,

Dividend = Divisior•Quotient + Remainder

Thus ,

=> 117 = 52×2 + 13

=> 13 = 117 - 52×2

=> 13 = 52×(-2) + 117×1

=> HCF(52 , 117) = 52×(-2) + 117×1

Clearly ,

HCF(52 , 117) is of the form 52x + 117y , where x = -2 and y = 1 .

Hence ,

HCF(52 , 117) = 13 = 52×(-2) + 117×1